$\lim_{x\to0}\left(xe^{2x}\right)$
$dx=x\sqrt{x^2-1}\:dy,\:y\left(4\right)=0$
$\frac{d}{dx}\left(x^{-2\sqrt{x}}\right)$
$\frac{4x^2y^3}{2xy^3}$
$\sqrt{\frac{y}{2z}}$
$5-x^2=3-x$
$\left(2xy+\frac{1}{4}y^2\right)^2$
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