$-5r+\:8r\:+\:5$
$x^3-4x^2-6x+5$
$3x\frac{dy}{dx}-y=\ln\left(x\right)+1$
$\int_0^{6\pi}\tan\left(x\right)dx$
$y=\left(x^3-4x\right)^5-2x^{\frac{1}{3}}-2x^{-3}$
$x^2+2x-15x^2$
$f\left(x\right)=x^{3-12X-3}$
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