$\frac{d}{dx}\:y^3=4x$
$\left(c+13\right)\left(c-13\right)$
$32-4x=8$
$2\left(x+3\right)^5+5\left(x-3\right)^2$
$12x^2-x+4$
$2x^8\cdot4x^3$
$\left(2a-7\right).\left(2a+3\right)$
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