$\frac{5+3x}{4x+5}>1$
$\int\frac{\left(4x^2-5x+6\right)}{x-3}dx$
$\int6xe^8dx$
$20\cdot25$
$-10\left(3a\right)^0$
$10\left(-3\right)\left(4\right)-\left(-15\right)$
$m-n-m-n$
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