$\:\int\:\frac{9x+3}{x^3+3x^2-4x}dx$
$3c+4+6c$
$9x^2+108x$
$36cm^2\cdot6$
$-\frac{270}{-3}$
$\int-\frac{1}{9\:}\:cot\left(3x\right)sin\left(3x\right)\:dx$
$2s+9s$
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