$\left(3y-5x\right)^4$
$\frac{5x^{10}}{40x^2}$
$x^{12}-y^{14}$
$\frac{\left(x+3\right)\left(-2x\right)-\left(4-x^2\right)}{\left(x+3\right)^2}$
$x^2+10x+1c$
$-7n^3.\:-7n$
$5\int_0^2\left(3x\right)dx$
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