$3x+14=4x-6$
$\frac{x^3}{x^2-2x+4}$
$\frac{dy}{dx}=-\frac{y}{2}$
$3a\left(a-3\right)\left(a+3\right)$
$4x\left(\sin^2\left(x\right)-\cos\left(3x\right)\right)$
$0.69+0.38$
$6\cdot\left(2x+3y\right)^2$
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