$\lim\:_{x\to\:\infty\:}\left(\frac{6z^2+2z-7}{4z^3+2z-7}\right)$

$\frac{dy}{dx}=\frac{e^y}{x^2y}$

$\left(a^6\right)^6$

$\int3x^2\sin\left(2x\right)dx$

$x+5<8$

$\left(x^2-5x+1\right)-\left(3x-1\right)+\left(2x^2+3x-1\right)-\left(x^3+2x-5\right)$

$\lim_{x\to0}\frac{b\cdot\ln\left(1\right)}{0}$