$x^2-36=\:-9x$
$1+\left(\frac{\frac{1}{3}\left(5\right)}{3}\right)\left(\frac{11}{4}\right)-0.7$
$-\left|-7\right|=-7$
$\int_0^2cy^2dx$
$5-4\cdot3$
$\sqrt{c}+\frac{1}{\sqrt{c}}^2$
$11+7x-8x=-2\left(1-2x\right)+3$
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