$\left(x+2\left[\right]\left(x+4\right)\right)$
$\left(x\:+\:2\right)^2=\:32\:+\:\left(x\:-\:2\right)^2$
$y^{3}\cdoty^{2}=y$
$y=ln\left(x^2\right)$
$1.5\frac{dy}{dx}+\frac{1}{1.5}y\:=\:\frac{2}{3}$
$3x^2=27x$
$-\left(a+3b\right)+5c\left(a+3b\right)+5c$
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