$\left(a\right)+\:\left(\frac{1}{2}\right)^2$
$\frac{1}{4}j+\frac{1}{4}j$
$\left(6x^3-7y^4\right)^3$
$\left(+9\right)-\left(\left(+3\right)-\left(3-12\right)-\left(+8\right)\right)$
$-9+3x-12-4x$
$\left(6c^6n\right)^4$
$\sqrt{1+\frac{y^2}{25-y^2}}$
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