$\pi\int_1^3\left(2x+2\right)^2dx$
$7\left(5+2c\right)+3c$
$\int4^{3x+2}dx$
$\frac{\left(7x^6+3x^2\right)}{\left(\frac{4}{7}x^3+1\right)}$
$25^{x-2}=5^{3x}$
$+3\left(x^4+y^2\right)$
$\left(7a^2+5x^3\right)\:\left(7a^2+6x^2\right)$
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