$9x^2+42x=0$
$x^{2}-10x+25=64$
$5cosx-6=0$
$\sqrt{1-sin^{\left(\frac{2}{3}\right)}\left(x\right)}=cos^{\left(\frac{1}{3}\right)}\left(x\right)$
$cos\left(\theta\right)=-\frac{\sqrt{2}}{3}$
$18x^2=6x$
$\left(4x-3yz\right)^2$
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