$\int x\left(1-x^2-3x^5\right)dx$
$\int\frac{sec^2x}{tanx\left(tanx+1\right)}dx$
$3\left(4x+8\right)-8$
$\tan\:^{-1}\left(\frac{0.3}{1.8}\right)$
$4y^2-11y+6$
$-x^2+4x+12$
$x^2+6x+10+7$
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