$\frac{x^2-2x}{x^2+4x+8}$
$\left(2+i\right)^3\:,\:i=\sqrt{-1}$
$\frac{dx}{dt}=3t+2x$
$\left(\sqrt{3x^6-\sqrt{7\:\:}}y^5\right)^2$
$4x^2-\frac{8}{3}x+\frac{4}{9}\left(-2x+\frac{2}{3}\right)$
$-\:\lim_{x\to1}\sqrt[3]{2-3x^2}$
$ln\:\sqrt[4]{b}$
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