$y^3\cdot\left(120-x\right)^2$
$3x+x-3+2x^2+8x-5$
$25r^2-49$
$\int24x\left(6-x^2\right)^{\frac{1}{3}}dx$
$\int\frac{1+\sin\left(x\right)}{\sin\left(x\right).2\cos\left(x\right)}dx$
$\left(-4x-3\right)^3$
$6x-8=-8x+20$
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