$\frac{16}{2x}$

$\left(10xy\right)^2+80xy+160y$

$\frac{1}{\left(2tan\left(x\right)\right)^2\cdot sqrt\left(4+\left(2tan\left(x\right)\right)^2\right)}$

$3\left(2\right)+2\left(3\right)+9-4\left(-1\right)$

$\int\sec\left(y\right)^4\tan\left(y\right)^4dy$

$2x^2+3>x^2+19$

$-45-395$