$125x^2^2$
$\frac { d y } { d x } = 6 x ^ { 5 } \cdot e ^ { - y x }$
$8x+2=6x+4$
$\sqrt[6]{343a^9x^{12}}$
$\mid3-2x\mid\mid\:x+4\mid$
$\lim_{x\to\infty}\left(\frac{3-3cosx}{sin6x}\right)$
$\frac{125m^3-8n^3}{5m-2n}$
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