$\left(2\sqrt{x}+3\sqrt{y}\right)^2$
$\sqrt{4.04}$
$12x^3\:+\:6x^2-\:18x$
$2x^4y^{-8}z^{-1}$
$\frac{r}{\frac{r}{r}}$
$\left(\frac{8}{3}x^2-\frac{7}{4}x^3+\frac{1}{2}x-6\right)-\left(\frac{1}{3}x^4+\frac{1}{2}x^3-x+\frac{7}{2}\right)$
$x^2-2x-16$
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