$\lim_{x\to1}\left(\frac{x^3-x^2+x-1}{x+\ln\left(x\right)-1}\right)$
$4-\left(-7+4-5\right)$
$-\frac{3}{5}\cdot10+1$
$\frac{1}{x}+\frac{1}{x-1}=\frac{x+2}{6}$
$\frac{dy}{dt}=y^3-2y$
$h\left(x\right)=x^3\left(2x\right)$
$\left(2x+3y+2\right)\left(2x+3y-2\right)$
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