$\frac{sin^2t+6sin\:t+9}{sin\:t\:+3\:}=\frac{3\:csc\:t\:+1}{csc\:t}$
$\frac{sin^2x+cos^2x}{tan^2x}=cot^2x$
$6-\frac{1}{2}\cdot12$
$\sqrt[4]{x}-\frac{7}{\sqrt[3]{x}}$
$-22-\left(-3\right)$
$\csc\left(x\right)^2+2\csc\left(x\right)+1$
$x^2-14x-4=0$
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