$14+9\left(\frac{1}{3}\right)$
$x-9>4$
$\frac{5x^3-18x^2+12x+8}{4x^2-16x+16}$
$\frac{6x^2+4x+3}{2x}$
$\left(1100-135\right)+\left(680-75\right)+\left(800-120\right)+267$
$\int\frac{3x^2-3x+4}{4x^2+3x}dx$
$16-\left(-25-3\right)$
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