$tcp\:a^4-a^2b^2+\frac{b^4}{4}$
$z^4+4z^3-96z^2$
$\left(2x+5\:\right)\left(2x-5\:\right)$
$z^2+36z+324$
$m-5-5m+4$
$-7x-3y+3z=12$
$1.55^{0.0833333333}-1$
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