$6a-9-a^2$
$-13=2b-b-10$
$\frac{\left(12\cdot3+9\right)}{5}+7\cdot3$
$\left(3x^a\right)\left(x^3\right)$
$\frac{3b}{10b^3}$
$14x-5y+-3x+6y-8$
$x\left(8x^7\right)$
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