$-2\frac{\left(\left(x+3\right)\left(x-5\right)\left(x-7\right)\right)}{96}$
$\int_1^5e^{x^3}dx$
$=a^8-b^{12}$
$3^4.3^2$
$\left(\:-36\right)\:.\:\left(\:-73\right)$
$\frac{1}{\left(x+3\right)\left(x-3\right)}$
$\int_0^1\frac{\left(x-1\right)}{\left(x-3\right)\:\left(x-2\right)}dx$
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