$x^2+12x-8=0$
$\frac{\sin\left(x\right)+\cos\left(x\right)}{\frac{1}{\cos\left(x\right)}+\frac{1}{\sin\left(x\right)}}=\frac{\sin\left(2x\right)}{2}$
$153\cdot8$
$\lim_{x\to0}\left(\frac{3}{x}\right)^x$
$\lim_{x\to-3}\left(x^2-3x+9\right)$
$\frac{2x^3-4x^2-5}{x^2+3}$
$\left(44-6y\right)^2$
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