$\frac{6x+9}{5}\:\le2x-4$
$\frac { 4 } { x } = 2$
$\lim_{x\to0}\left(sinx\right)\left(\sqrt{\frac{1-x}{x}}\right)$
$x^4-18x^2+8$
$4\cos^2\left(\theta\right)=3$
$\frac{x^3+x}{\:\sqrt{1+x^2}}$
$10r-15r$
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