$\int_0^1\left(\frac{1}{1+12x^2}\right)dx$

$\int\frac{3}{4}x^3\sqrt[3]{6x+2}dx$

$\frac{\left(x^2+9\right)}{\left(x-3\right)}$

$18+\left(-9\right)-\left(-6\right)-12$

$\ln\left(x+31\right)-\ln\left(4-3x\right)=5\ln2$

$h\left(x\right)=\frac{2}{\sqrt{1-y^4}}$

$\cot\left(x\right)\left(\cos\left(^2\right)x-4\right)=0$