$\frac{\sqrt{xy^2}}{16}$
$x^2-x-200$
$xy'-y=2xy^2$
$\lim_{x\to1}\left(\frac{4\sin\left(\pi x\right)}{\cos\left(\pi x\right)+x}\right)$
$5\left(x-3\right)\ge2x+3\left(x-5\right)$
$x^2=-10x+24$
$\frac{12g^2}{25}.\:\frac{40}{9g^4}$
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