$\int\frac{\left(\sqrt{x}-b\right)^{2}}{\sqrt{x}}dx$
$\frac{6}{\sqrt[2]{9-4x}}$
$\lim_{x\to8}\left(\frac{1-\cos\left(x-8\right)}{ln^2\left(x-7\right)}\right)$
$2\left(\frac{2}{3}a^3-1\right)^3$
$9b^2-7b^2-7+7$
$9-4x\ge-3$
$x^2+9x-8$
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