$\left(3x+6y\right)^3$
$6x-mx=2+m$
$\lim_{x\to0}\left(\frac{lncosx}{lntanx}\right)$
$\frac{x^3-2x+4}{3x^2-1}$
$\frac{d}{dx}\left(\frac{y}{tanxy}-x=2\right)$
$12-\left(+16-11+3\right)$
$\tan\left(2x\right)\sin\left(x\right)-\sin\left(x\right)-\tan\left(2x\right)+1=0$
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