$7 x + 3 \geq 5$
$\frac{d^3}{dx^3}\left(x^3-6x^2-5x+3\right)$
$\frac{dy}{dx}=20yx^4$
$4x^2-24x+100=0$
$\int\left(\frac{1}{\sqrt{6+x^2}}\right)dx$
$3x\cdot y^5x^3\cdot y^4$
$16cosx-3=\sqrt{128}-3$
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