$10\left(2x\right)^2\left(3\right)^3$
$2\left(x+2\right)+3\left(x-1\right)=11$
$\sin^2g$
$\left(10+2a+3b\right)\left(10-2a+3b\right)$
$8r+12p-7-3p$
$5^2+2\left(5\right)+2\left(5\right)+5^2$
$\frac{7^5x\:7^3}{7^2}$
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