$\frac{2}{x\sqrt{x}}$
$\sqrt{12x}\cdot\sqrt{3x^3}$
$\left(x-5\right)\left(x+2\right)\le0$
$\frac{2a-4}{6}<2$
$3-4x^2+x^4-2x^3\cdot x^3-1+2x$
$-36\cdot4$
$-3x^2+2xy+1y^2$
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