$\frac{x^2+3}{x\left(x^2+x+6\right)}$
$21+4\left(3^2-5\right)$
$\left(y^2=2x\right)$
$c^2-48c-8$
$\left(4.3x\:+\:3y\right)+\:\left(4.7x+13.8y\right)$
$20+90+516$
$\frac{\left(2x^3+9x^3-4x+10\right)}{\left(x+5\right)}$
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