$\frac{dy}{dx}\left(\tan\left(xy\right)=-\sin\left(xy\right)\right)$

$-5x^3+4x+3x^2-2x+5x^3$

$\frac{dt}{dx}=a-bx$

$\int\:\left(3y^2+6y\right)^4\left(y+1\right)dy$

$45:\{-2+12:\left(-7+3\right)+12-[\left(-24\right):\left(\left(-3\right)\cdot5+7\right)]+5\}$

$\left(+4\right).\left(-5\right)+\left(-12\right)$

$\left(x^4+2x^3-7x^2-8x+12\right)$