$\frac{d}{dx}\left(-12xy=0\right)$
$\int6^{x+3}dx$
$x^2-21x+441$
$\left(\frac{\left(-2x\right)^2}{3xy^2}\right)^3$
$-24-+-48$
$\lim_{x\to0}\left(\frac{1}{\frac{x\:+\:2\:-\:\frac{1}{2}}{x}}\right)$
$3x+4<x+10$
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