$36^{x+3}=6^{x-1}$
$y^4+y^2+y=0$
$12\cdot\left(-1\right)\cdot\left(-2\right)$
$4\left(4p+4\right)$
$3+2-11+4+15+7-2-3-5+26+1+2$
$-x^3+6x^2+15x+8$
$\frac{dy}{dx}=9x^2\left(3+y^2\right)^{\frac{3}{2}}$
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