$\cos\left(x-\frac{\pi}{8}\right)=\frac{1}{\sqrt{2}}$
$f\left(2\right)=8\left(2\right)+5\left(2\right)^4-3\left(2\right)^2-2^3$
$4abx^3-8b^2x^2y\sqrt{2bx^2}$
$x^2-2x+100=0$
$55,13-44,50$
$3x\ge6x+9$
$x^3+4x^2-x-10$
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