$\left(x+y\right)^4=2x$
$4\left(7-12\right)^2-5\left(4-7\right)^2$
$\int\:\frac{x^2-3x+5}{x^3}dx$
$\left(4p^2+6p\right)\left(4p^2-6p\right)$
$x=lny'+siny'$
$\lim_{x\to-\infty}\left(\arctan\left(0\right)-\arctan\left(x\right)\right)$
$x^2+3y\frac{dy}{dx}=0$
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