$\left(m^6+3\right)\left(m^4+1\right)$
$\ln5x$
$\frac{1}{cos\left(x\right)sec\left(-x\right)}$
$\frac{-x^3+x^2-2}{-x^3-x+1}$
$\lim_{x\to4}\left(\frac{x^2+4x-32}{x^2-6x+8}\right)$
$3x^2-8x-27=0$
$\left(4ab+7c\right)\left(ab+6c\right)$
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