$\frac{4}{x}\ge3$
$\left(x+1\right)\left(x-2\right)\le0$
$2x-3\le4x+1$
$3x^2=121$
$\left(5^0\right)^8$
$1+cos2a=2cos^2a$
$\frac{x^2+5x+2}{x+1}$
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