$\frac{m^4-1}{1+m^2}$
$\left(1-2x\right)\cdot\left(3x-7\right)$
$3^{x^2-7x-\frac{11}{2}}=9\sqrt{3}$
$\lim_{x\to\infty}\left(\frac{2x+1}{5x+3}\right)^x$
$\frac{x^4-2x^3-6x^2-11x+2}{x^3-3x^2+2x}$
$x2-16x$
$x+2y+z=700$
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