$\left(-4x^4-5\right)^3\:$
$\int\left(6x^3-9x^2+7x-2\right)dx$
$\left(2+3x^4-x\:^3\right):\:\left(x-3\right)$
$x-3>7$
$-2x^2-x=6$
$\left(2x^3+\frac{1}{x}\right)^2$
$\left[\left(-4\right)-\left(+7-5\right)+\left(-12\right)\right]$
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