$z^6-4z^3+4$
$3^7.3^{-4}$
$\int x^2\left(3x^3-2\right)^3dx$
$-8-\left(-10\right)^2$
$7\:+\left(4-9\right).\left(7-5.3\right)+6$
$\frac{16m^3}{-60n^6}$
$x^2=\frac{16}{169}$
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