$\frac{1}{2}a+\frac{1}{3}b+\frac{1}{4}c-d,\:a=2,\:b=4,\:c=3,\:d\:=-25$
$2x-3<1-x$
$3\cos^2\left(x\right)-\cos\left(2x\right)=1$
$\left(\tan\left(x-1\right)\right)\left(\sqrt{3}\tan\left(+1\right)\right)=0$
$7^{-3}\cdot7^4$
$\sqrt{49x^4}$
$\frac{2}{7}x+\frac{3}{\left(4\right)x}$
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