$3x-4y-8x+y-9$
$\frac{-6x+4}{2}$
$\left(y-6\right)\left(xy-y+4\right)$
$-\left(-75\right)+\left(-\left|75\right|\right)$
$\int tan3\:5x\:dx$
$28>2-3>-14$
$\frac{y}{x+1}\cdot\frac{dy}{dx}=\frac{y^2+1}{x}$
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