$x^2-12x=-36$
$\frac{4x}{\left(1+4x\right)^2}$
$-2+3+1-2+4+2-4-5$
$\left(5t+3\right)^2$
$-4x+\frac{3-2x}{4}>\frac{1-3x}{3}-\frac{37}{12}$
$2\left(x-y\right)-3\left(x-y\right)$
$\left(5x-y\right)^3$
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