$\left(2x+3\right)\left(3x-1\right)\left(x-2\right)$

$\lim_{x\to1}4x^3-7x+6$

$\frac{d}{dx}\frac{4}{x^4}+\frac{1}{x}+2$

$3+0.5\left(12\right)$

$\lim_{x\to\infty}\left(x^2+1\right)^{\frac{1}{x}}$

$2x+5+x+2+2x+5+x+2$

$\lim_{x\to\infty}\:\frac{\left(3x^2+1\right)\cdot\left(5x+3\right)}{x^2-7x+9}$