$\int_0^2\left(sec^2x-1\right)sec\left(x\right)\:tan\left(x\right)dx$

$\int\:-\frac{5}{3}\left(2x-5\right)^4dx$

$2\cot\left(x\right)+1=3$

$\left(x^2+1\right)y''$

$\frac{d}{dx}\left(e^{xy}=sen^{-1}\left(tanhy\right)\right)$

$5\left(-2-8\right)-9\left(1-9\right)+22\left(2-1\right)-3\left(3-1\right)$

$\left(ab^2-4c\right)^3$